Optimal. Leaf size=59 \[ -\frac {a^3 \coth (c+d x)}{d}-\frac {b^2 (3 a+b) \tanh (c+d x)}{d}+x (a+b)^3-\frac {b^3 \tanh ^3(c+d x)}{3 d} \]
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Rubi [A] time = 0.08, antiderivative size = 59, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.130, Rules used = {3670, 461, 207} \[ -\frac {a^3 \coth (c+d x)}{d}-\frac {b^2 (3 a+b) \tanh (c+d x)}{d}+x (a+b)^3-\frac {b^3 \tanh ^3(c+d x)}{3 d} \]
Antiderivative was successfully verified.
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Rule 207
Rule 461
Rule 3670
Rubi steps
\begin {align*} \int \coth ^2(c+d x) \left (a+b \tanh ^2(c+d x)\right )^3 \, dx &=\frac {\operatorname {Subst}\left (\int \frac {\left (a+b x^2\right )^3}{x^2 \left (1-x^2\right )} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac {\operatorname {Subst}\left (\int \left (-b^2 (3 a+b)+\frac {a^3}{x^2}-b^3 x^2-\frac {(a+b)^3}{-1+x^2}\right ) \, dx,x,\tanh (c+d x)\right )}{d}\\ &=-\frac {a^3 \coth (c+d x)}{d}-\frac {b^2 (3 a+b) \tanh (c+d x)}{d}-\frac {b^3 \tanh ^3(c+d x)}{3 d}-\frac {(a+b)^3 \operatorname {Subst}\left (\int \frac {1}{-1+x^2} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=(a+b)^3 x-\frac {a^3 \coth (c+d x)}{d}-\frac {b^2 (3 a+b) \tanh (c+d x)}{d}-\frac {b^3 \tanh ^3(c+d x)}{3 d}\\ \end {align*}
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Mathematica [A] time = 2.31, size = 81, normalized size = 1.37 \[ \frac {\tanh (c+d x) \left (-3 a^3 \coth ^2(c+d x)-b^2 \left (9 a+b \tanh ^2(c+d x)+3 b\right )+3 (a+b)^3 \sqrt {\coth ^2(c+d x)} \tanh ^{-1}\left (\sqrt {\coth ^2(c+d x)}\right )\right )}{3 d} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.43, size = 341, normalized size = 5.78 \[ -\frac {{\left (3 \, a^{3} + 9 \, a b^{2} + 4 \, b^{3}\right )} \cosh \left (d x + c\right )^{4} - 4 \, {\left (3 \, a^{3} + 9 \, a b^{2} + 4 \, b^{3} + 3 \, {\left (a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}\right )} d x\right )} \cosh \left (d x + c\right ) \sinh \left (d x + c\right )^{3} + {\left (3 \, a^{3} + 9 \, a b^{2} + 4 \, b^{3}\right )} \sinh \left (d x + c\right )^{4} + 9 \, a^{3} - 9 \, a b^{2} + 4 \, {\left (3 \, a^{3} - b^{3}\right )} \cosh \left (d x + c\right )^{2} + 2 \, {\left (6 \, a^{3} - 2 \, b^{3} + 3 \, {\left (3 \, a^{3} + 9 \, a b^{2} + 4 \, b^{3}\right )} \cosh \left (d x + c\right )^{2}\right )} \sinh \left (d x + c\right )^{2} - 4 \, {\left ({\left (3 \, a^{3} + 9 \, a b^{2} + 4 \, b^{3} + 3 \, {\left (a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}\right )} d x\right )} \cosh \left (d x + c\right )^{3} + {\left (3 \, a^{3} + 9 \, a b^{2} + 4 \, b^{3} + 3 \, {\left (a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}\right )} d x\right )} \cosh \left (d x + c\right )\right )} \sinh \left (d x + c\right )}{12 \, {\left (d \cosh \left (d x + c\right ) \sinh \left (d x + c\right )^{3} + {\left (d \cosh \left (d x + c\right )^{3} + d \cosh \left (d x + c\right )\right )} \sinh \left (d x + c\right )\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.41, size = 135, normalized size = 2.29 \[ \frac {3 \, {\left (a^{3} + 3 \, a^{2} b + 3 \, a b^{2} + b^{3}\right )} {\left (d x + c\right )} - \frac {6 \, a^{3}}{e^{\left (2 \, d x + 2 \, c\right )} - 1} + \frac {2 \, {\left (9 \, a b^{2} e^{\left (4 \, d x + 4 \, c\right )} + 6 \, b^{3} e^{\left (4 \, d x + 4 \, c\right )} + 18 \, a b^{2} e^{\left (2 \, d x + 2 \, c\right )} + 6 \, b^{3} e^{\left (2 \, d x + 2 \, c\right )} + 9 \, a b^{2} + 4 \, b^{3}\right )}}{{\left (e^{\left (2 \, d x + 2 \, c\right )} + 1\right )}^{3}}}{3 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.25, size = 80, normalized size = 1.36 \[ \frac {a^{3} \left (d x +c -\coth \left (d x +c \right )\right )+3 a^{2} b \left (d x +c \right )+3 a \,b^{2} \left (d x +c -\tanh \left (d x +c \right )\right )+b^{3} \left (d x +c -\tanh \left (d x +c \right )-\frac {\left (\tanh ^{3}\left (d x +c \right )\right )}{3}\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.34, size = 147, normalized size = 2.49 \[ \frac {1}{3} \, b^{3} {\left (3 \, x + \frac {3 \, c}{d} - \frac {4 \, {\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + 2\right )}}{d {\left (3 \, e^{\left (-2 \, d x - 2 \, c\right )} + 3 \, e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )} + 1\right )}}\right )} + 3 \, a b^{2} {\left (x + \frac {c}{d} - \frac {2}{d {\left (e^{\left (-2 \, d x - 2 \, c\right )} + 1\right )}}\right )} + a^{3} {\left (x + \frac {c}{d} + \frac {2}{d {\left (e^{\left (-2 \, d x - 2 \, c\right )} - 1\right )}}\right )} + 3 \, a^{2} b x \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.31, size = 218, normalized size = 3.69 \[ x\,{\left (a+b\right )}^3+\frac {\frac {2\,a\,b^2}{d}+\frac {2\,{\mathrm {e}}^{2\,c+2\,d\,x}\,\left (2\,b^3+3\,a\,b^2\right )}{3\,d}}{2\,{\mathrm {e}}^{2\,c+2\,d\,x}+{\mathrm {e}}^{4\,c+4\,d\,x}+1}+\frac {\frac {2\,\left (2\,b^3+3\,a\,b^2\right )}{3\,d}+\frac {2\,{\mathrm {e}}^{4\,c+4\,d\,x}\,\left (2\,b^3+3\,a\,b^2\right )}{3\,d}+\frac {4\,a\,b^2\,{\mathrm {e}}^{2\,c+2\,d\,x}}{d}}{3\,{\mathrm {e}}^{2\,c+2\,d\,x}+3\,{\mathrm {e}}^{4\,c+4\,d\,x}+{\mathrm {e}}^{6\,c+6\,d\,x}+1}-\frac {2\,a^3}{d\,\left ({\mathrm {e}}^{2\,c+2\,d\,x}-1\right )}+\frac {2\,\left (2\,b^3+3\,a\,b^2\right )}{3\,d\,\left ({\mathrm {e}}^{2\,c+2\,d\,x}+1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a + b \tanh ^{2}{\left (c + d x \right )}\right )^{3} \coth ^{2}{\left (c + d x \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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